Base | Representation |
---|---|
bin | 10010110101001110… |
… | …00000110101000001 |
3 | 222002120221212002002 |
4 | 21122213000311001 |
5 | 131201142023131 |
6 | 4351114433345 |
7 | 505352345252 |
oct | 113247006501 |
9 | 28076855062 |
10 | 10110111041 |
11 | 4318992078 |
12 | 1b61a32855 |
13 | c51761234 |
14 | 6bca26b29 |
15 | 3e28ad6cb |
hex | 25a9c0d41 |
10110111041 has 2 divisors, whose sum is σ = 10110111042. Its totient is φ = 10110111040.
The previous prime is 10110111019. The next prime is 10110111043. The reversal of 10110111041 is 14011101101.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8748796225 + 1361314816 = 93535^2 + 36896^2 .
It is a cyclic number.
It is not a de Polignac number, because 10110111041 - 26 = 10110110977 is a prime.
It is a super-2 number, since 2×101101110412 (a number of 21 digits) contains 22 as substring.
Together with 10110111043, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10110111043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055055520 + 5055055521.
It is an arithmetic number, because the mean of its divisors is an integer number (5055055521).
Almost surely, 210110111041 is an apocalyptic number.
It is an amenable number.
10110111041 is a deficient number, since it is larger than the sum of its proper divisors (1).
10110111041 is an equidigital number, since it uses as much as digits as its factorization.
10110111041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 11.
Adding to 10110111041 its reverse (14011101101), we get a palindrome (24121212142).
The spelling of 10110111041 in words is "ten billion, one hundred ten million, one hundred eleven thousand, forty-one".
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