10110113119 has 2 divisors, whose sum is σ = 10110113120. Its totient is φ = 10110113118.

The previous prime is 10110113093. The next prime is 10110113147. The reversal of 10110113119 is 91131101101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10110113119 is a prime.

It is a super-3 number, since 3×10110113119³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 10110113096 and 10110113105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110113149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055056559 + 5055056560.

It is an arithmetic number, because the mean of its divisors is an integer number (5055056560).

Almost surely, 2^10110113119 is an apocalyptic number.

10110113119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110113119 is an equidigital number, since it uses as much as digits as its factorization.

10110113119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27, while the sum is 19.

The spelling of 10110113119 in words is "ten billion, one hundred ten million, one hundred thirteen thousand, one hundred nineteen".