Base | Representation |
---|---|
bin | 101111000101000100… |
… | …1111110110010010011 |
3 | 100122221222110211210001 |
4 | 1132022021332302103 |
5 | 3124024120320313 |
6 | 114240133150431 |
7 | 10206255561406 |
oct | 1361211766223 |
9 | 318858424701 |
10 | 101102120083 |
11 | 39971569248 |
12 | 17716a8b417 |
13 | 96c2c533c3 |
14 | 4c71591d3d |
15 | 296ad8dadd |
hex | 178a27ec93 |
101102120083 has 2 divisors, whose sum is σ = 101102120084. Its totient is φ = 101102120082.
The previous prime is 101102120081. The next prime is 101102120101. The reversal of 101102120083 is 380021201101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101102120083 - 21 = 101102120081 is a prime.
Together with 101102120081, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 101102120083.
It is not a weakly prime, because it can be changed into another prime (101102120081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50551060041 + 50551060042.
It is an arithmetic number, because the mean of its divisors is an integer number (50551060042).
Almost surely, 2101102120083 is an apocalyptic number.
101102120083 is a deficient number, since it is larger than the sum of its proper divisors (1).
101102120083 is an equidigital number, since it uses as much as digits as its factorization.
101102120083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 101102120083 its reverse (380021201101), we get a palindrome (481123321184).
The spelling of 101102120083 in words is "one hundred one billion, one hundred two million, one hundred twenty thousand, eighty-three".
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