Base | Representation |
---|---|
bin | 10110111111010010011111… |
… | …010001110110100000100011 |
3 | 111020222122210002022010000102 |
4 | 112333102133101312200203 |
5 | 101223011000303424044 |
6 | 555011314223213015 |
7 | 30203452643350016 |
oct | 2677223721664043 |
9 | 436878702263012 |
10 | 101106202404899 |
11 | 2a24099947382a |
12 | b40b08674716b |
13 | 4455373c06a93 |
14 | 1ad77cdd3537d |
15 | ba500ea3a24e |
hex | 5bf49f476823 |
101106202404899 has 2 divisors, whose sum is σ = 101106202404900. Its totient is φ = 101106202404898.
The previous prime is 101106202404887. The next prime is 101106202404901. The reversal of 101106202404899 is 998404202601101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101106202404899 - 232 = 101101907437603 is a prime.
It is a super-2 number, since 2×1011062024048992 (a number of 29 digits) contains 22 as substring.
Together with 101106202404901, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (101106202404199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50553101202449 + 50553101202450.
It is an arithmetic number, because the mean of its divisors is an integer number (50553101202450).
Almost surely, 2101106202404899 is an apocalyptic number.
101106202404899 is a deficient number, since it is larger than the sum of its proper divisors (1).
101106202404899 is an equidigital number, since it uses as much as digits as its factorization.
101106202404899 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 47.
The spelling of 101106202404899 in words is "one hundred one trillion, one hundred six billion, two hundred two million, four hundred four thousand, eight hundred ninety-nine".
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