Base | Representation |
---|---|
bin | 10110111111010110001101… |
… | …101000000111111110011111 |
3 | 111021000001002202210000111022 |
4 | 112333112031220013332133 |
5 | 101223042143003033043 |
6 | 555013215111514355 |
7 | 30203654020623041 |
oct | 2677261550077637 |
9 | 437001082700438 |
10 | 101110201221023 |
11 | 2a242660719545 |
12 | b40ba019889bb |
13 | 4455860502677 |
14 | 1ad7a8d05ba91 |
15 | ba5195b29868 |
hex | 5bf58da07f9f |
101110201221023 has 2 divisors, whose sum is σ = 101110201221024. Its totient is φ = 101110201221022.
The previous prime is 101110201220953. The next prime is 101110201221059. The reversal of 101110201221023 is 320122102011101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101110201221023 - 210 = 101110201219999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101110201220992 and 101110201221010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101110201221823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555100610511 + 50555100610512.
It is an arithmetic number, because the mean of its divisors is an integer number (50555100610512).
Almost surely, 2101110201221023 is an apocalyptic number.
101110201221023 is a deficient number, since it is larger than the sum of its proper divisors (1).
101110201221023 is an equidigital number, since it uses as much as digits as its factorization.
101110201221023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 101110201221023 its reverse (320122102011101), we get a palindrome (421232303232124).
The spelling of 101110201221023 in words is "one hundred one trillion, one hundred ten billion, two hundred one million, two hundred twenty-one thousand, twenty-three".
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