101111113213333 has 2 divisors, whose sum is σ = 101111113213334. Its totient is φ = 101111113213332.

The previous prime is 101111113213283. The next prime is 101111113213343. The reversal of 101111113213333 is 333312311111101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97132496558724 + 3978616654609 = 9855582^2 + 1994647^2 .

It is a cyclic number.

It is not a de Polignac number, because 101111113213333 - 2⁴⁵ = 65926741124501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101111113213298 and 101111113213307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101111113213343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50555556606666 + 50555556606667.

It is an arithmetic number, because the mean of its divisors is an integer number (50555556606667).

Almost surely, 2^{101111113213333} is an apocalyptic number.

It is an amenable number.

101111113213333 is a deficient number, since it is larger than the sum of its proper divisors (1).

101111113213333 is an equidigital number, since it uses as much as digits as its factorization.

101111113213333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 25.

Adding to 101111113213333 its reverse (333312311111101), we get a palindrome (434423424324434).

The spelling of 101111113213333 in words is "one hundred one trillion, one hundred eleven billion, one hundred thirteen million, two hundred thirteen thousand, three hundred thirty-three".