Base | Representation |
---|---|
bin | 11101011011010111000… |
… | …00100110000100100111 |
3 | 10120122212202120211121222 |
4 | 32231223200212010213 |
5 | 113031233440134343 |
6 | 2052300320330555 |
7 | 133023343605305 |
oct | 16555340460447 |
9 | 3518782524558 |
10 | 1011121021223 |
11 | 35a8a5502825 |
12 | 143b66473a5b |
13 | 7446b2b6b81 |
14 | 36d1d41b275 |
15 | 1b47cc5da68 |
hex | eb6b826127 |
1011121021223 has 2 divisors, whose sum is σ = 1011121021224. Its totient is φ = 1011121021222.
The previous prime is 1011121021181. The next prime is 1011121021237. The reversal of 1011121021223 is 3221201211101.
It is a happy number.
1011121021223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1011121021223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011121011223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505560510611 + 505560510612.
It is an arithmetic number, because the mean of its divisors is an integer number (505560510612).
Almost surely, 21011121021223 is an apocalyptic number.
1011121021223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011121021223 is an equidigital number, since it uses as much as digits as its factorization.
1011121021223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1011121021223 its reverse (3221201211101), we get a palindrome (4232322232324).
The spelling of 1011121021223 in words is "one trillion, eleven billion, one hundred twenty-one million, twenty-one thousand, two hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •