10111213031 has 2 divisors, whose sum is σ = 10111213032. Its totient is φ = 10111213030.

The previous prime is 10111213003. The next prime is 10111213069. The reversal of 10111213031 is 13031211101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10111213031 is a prime.

It is a super-2 number, since 2×10111213031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10111212997 and 10111213015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111213001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055606515 + 5055606516.

It is an arithmetic number, because the mean of its divisors is an integer number (5055606516).

Almost surely, 2^10111213031 is an apocalyptic number.

10111213031 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111213031 is an equidigital number, since it uses as much as digits as its factorization.

10111213031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 10111213031 its reverse (13031211101), we get a palindrome (23142424132).

The spelling of 10111213031 in words is "ten billion, one hundred eleven million, two hundred thirteen thousand, thirty-one".