101112200110081 has 2 divisors, whose sum is σ = 101112200110082. Its totient is φ = 101112200110080.

The previous prime is 101112200110039. The next prime is 101112200110219. The reversal of 101112200110081 is 180011002211101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58145276343025 + 42966923767056 = 7625305^2 + 6554916^2 .

It is a cyclic number.

It is not a de Polignac number, because 101112200110081 - 2¹¹ = 101112200108033 is a prime.

It is a super-4 number, since 4×101112200110081⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (101112200110781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556100055040 + 50556100055041.

It is an arithmetic number, because the mean of its divisors is an integer number (50556100055041).

Almost surely, 2^{101112200110081} is an apocalyptic number.

It is an amenable number.

101112200110081 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112200110081 is an equidigital number, since it uses as much as digits as its factorization.

101112200110081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 19.

Adding to 101112200110081 its reverse (180011002211101), we get a palindrome (281123202321182).

The spelling of 101112200110081 in words is "one hundred one trillion, one hundred twelve billion, two hundred million, one hundred ten thousand, eighty-one".