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101112212143 is a prime number
BaseRepresentation
bin101111000101011000…
…0011110101010101111
3100122222200110120111001
41132022300132222233
53124034211242033
6114241133341131
710206440423335
oct1361260365257
9318880416431
10101112212143
1139977231598
121771a3377a7
1396c5077b37
144c72a5bb55
15296bbd3e7d
hex178ac1eaaf

101112212143 has 2 divisors, whose sum is σ = 101112212144. Its totient is φ = 101112212142.

The previous prime is 101112212023. The next prime is 101112212147. The reversal of 101112212143 is 341212211101.

It is a strong prime.

It is an emirp because it is prime and its reverse (341212211101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101112212143 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101112212143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101112212147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50556106071 + 50556106072.

It is an arithmetic number, because the mean of its divisors is an integer number (50556106072).

Almost surely, 2101112212143 is an apocalyptic number.

101112212143 is a deficient number, since it is larger than the sum of its proper divisors (1).

101112212143 is an equidigital number, since it uses as much as digits as its factorization.

101112212143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 101112212143 its reverse (341212211101), we get a palindrome (442324423244).

The spelling of 101112212143 in words is "one hundred one billion, one hundred twelve million, two hundred twelve thousand, one hundred forty-three".