10111311012301 has 2 divisors, whose sum is σ = 10111311012302. Its totient is φ = 10111311012300.

The previous prime is 10111311012197. The next prime is 10111311012317. The reversal of 10111311012301 is 10321011311101.

It is an a-pointer prime, because the next prime (10111311012317) can be obtained adding 10111311012301 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9239618026276 + 871692986025 = 3039674^2 + 933645^2 .

It is a cyclic number.

It is not a de Polignac number, because 10111311012301 - 2¹⁵ = 10111310979533 is a prime.

It is a super-2 number, since 2×10111311012301² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10111311012701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055655506150 + 5055655506151.

It is an arithmetic number, because the mean of its divisors is an integer number (5055655506151).

Almost surely, 2^{10111311012301} is an apocalyptic number.

It is an amenable number.

10111311012301 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111311012301 is an equidigital number, since it uses as much as digits as its factorization.

10111311012301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 10111311012301 its reverse (10321011311101), we get a palindrome (20432322323402).

The spelling of 10111311012301 in words is "ten trillion, one hundred eleven billion, three hundred eleven million, twelve thousand, three hundred one".