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10111313142241 is a prime number
BaseRepresentation
bin1001001100100011100100…
…1110100110000111100001
31022210122001210112202201021
42103020321032212013201
52311130432131022431
633301023444005441
72062342523422633
oct223107116460741
938718053482637
1010111313142241
113249202738353
121173782390881
1358465371226c
1426d566894a53
15128042474b11
hex932393a61e1

10111313142241 has 2 divisors, whose sum is σ = 10111313142242. Its totient is φ = 10111313142240.

The previous prime is 10111313142239. The next prime is 10111313142253. The reversal of 10111313142241 is 14224131311101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9820796454225 + 290516688016 = 3133815^2 + 538996^2 .

It is a cyclic number.

It is not a de Polignac number, because 10111313142241 - 21 = 10111313142239 is a prime.

Together with 10111313142239, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (10111311142241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055656571120 + 5055656571121.

It is an arithmetic number, because the mean of its divisors is an integer number (5055656571121).

Almost surely, 210111313142241 is an apocalyptic number.

It is an amenable number.

10111313142241 is a deficient number, since it is larger than the sum of its proper divisors (1).

10111313142241 is an equidigital number, since it uses as much as digits as its factorization.

10111313142241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 10111313142241 its reverse (14224131311101), we get a palindrome (24335444453342).

The spelling of 10111313142241 in words is "ten trillion, one hundred eleven billion, three hundred thirteen million, one hundred forty-two thousand, two hundred forty-one".