1011133011300 has 72 divisors (see below), whose sum is σ = 2930615616096. Its totient is φ = 269168117760.

The previous prime is 1011133011263. The next prime is 1011133011373. The reversal of 1011133011300 is 31103311101.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1011133011300.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2747562 + ... + 3093761.

It is an arithmetic number, because the mean of its divisors is an integer number (40702994668).

Almost surely, 2^{1011133011300} is an apocalyptic number.

1011133011300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1011133011300 is an abundant number, since it is smaller than the sum of its proper divisors (1919482604796).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011133011300 is a wasteful number, since it uses less digits than its factorization.

1011133011300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5841917 (or 5841910 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 1011133011300 its reverse (31103311101), we get a palindrome (1042236322401).

The spelling of 1011133011300 in words is "one trillion, eleven billion, one hundred thirty-three million, eleven thousand, three hundred".