1011140113410 has 64 divisors (see below), whose sum is σ = 3081569875200. Its totient is φ = 231117739776.

The previous prime is 1011140113381. The next prime is 1011140113439. The reversal of 1011140113410 is 143110411101.

1011140113410 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 140 + 113 + 410 = 666.

It is an interprime number because it is at equal distance from previous prime (1011140113381) and next prime (1011140113439).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 267495495 + ... + 267499274.

It is an arithmetic number, because the mean of its divisors is an integer number (48149529300).

Almost surely, 2^{1011140113410} is an apocalyptic number.

1011140113410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1011140113410 is an abundant number, since it is smaller than the sum of its proper divisors (2070429761790).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011140113410 is a wasteful number, since it uses less digits than its factorization.

1011140113410 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 534994792 (or 534994786 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 1011140113410 its reverse (143110411101), we get a palindrome (1154250524511).

The spelling of 1011140113410 in words is "one trillion, eleven billion, one hundred forty million, one hundred thirteen thousand, four hundred ten".