101120010112181 has 2 divisors, whose sum is σ = 101120010112182. Its totient is φ = 101120010112180.

The previous prime is 101120010112103. The next prime is 101120010112229. The reversal of 101120010112181 is 181211010021101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 56689906732900 + 44430103379281 = 7529270^2 + 6665591^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101120010112181 is a prime.

It is a super-2 number, since 2×101120010112181² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101120010112081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560005056090 + 50560005056091.

It is an arithmetic number, because the mean of its divisors is an integer number (50560005056091).

Almost surely, 2^{101120010112181} is an apocalyptic number.

It is an amenable number.

101120010112181 is a deficient number, since it is larger than the sum of its proper divisors (1).

101120010112181 is an equidigital number, since it uses as much as digits as its factorization.

101120010112181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32, while the sum is 20.

Adding to 101120010112181 its reverse (181211010021101), we get a palindrome (282331020133282).

The spelling of 101120010112181 in words is "one hundred one trillion, one hundred twenty billion, ten million, one hundred twelve thousand, one hundred eighty-one".