101120111100221 has 2 divisors, whose sum is σ = 101120111100222. Its totient is φ = 101120111100220.

The previous prime is 101120111100103. The next prime is 101120111100223. The reversal of 101120111100221 is 122001111021101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61574702772025 + 39545408328196 = 7846955^2 + 6288514^2 .

It is a cyclic number.

It is not a de Polignac number, because 101120111100221 - 2¹⁸ = 101120110838077 is a prime.

Together with 101120111100223, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101120111100196 and 101120111100205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101120111100223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560055550110 + 50560055550111.

It is an arithmetic number, because the mean of its divisors is an integer number (50560055550111).

Almost surely, 2^{101120111100221} is an apocalyptic number.

It is an amenable number.

101120111100221 is a deficient number, since it is larger than the sum of its proper divisors (1).

101120111100221 is an equidigital number, since it uses as much as digits as its factorization.

101120111100221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 101120111100221 its reverse (122001111021101), we get a palindrome (223121222121322).

The spelling of 101120111100221 in words is "one hundred one trillion, one hundred twenty billion, one hundred eleven million, one hundred thousand, two hundred twenty-one".