101120113142143 has 2 divisors, whose sum is σ = 101120113142144. Its totient is φ = 101120113142142.

The previous prime is 101120113142117. The next prime is 101120113142183. The reversal of 101120113142143 is 341241311021101.

It is a weak prime.

It is an emirp because it is prime and its reverse (341241311021101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101120113142143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101120113142183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560056571071 + 50560056571072.

It is an arithmetic number, because the mean of its divisors is an integer number (50560056571072).

Almost surely, 2^{101120113142143} is an apocalyptic number.

101120113142143 is a deficient number, since it is larger than the sum of its proper divisors (1).

101120113142143 is an equidigital number, since it uses as much as digits as its factorization.

101120113142143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 101120113142143 its reverse (341241311021101), we get a palindrome (442361424163244).

The spelling of 101120113142143 in words is "one hundred one trillion, one hundred twenty billion, one hundred thirteen million, one hundred forty-two thousand, one hundred forty-three".