1011211300 has 72 divisors (see below), whose sum is σ = 2406845952. Its totient is φ = 365712000.

The previous prime is 1011211283. The next prime is 1011211303. The reversal of 1011211300 is 31121101.

It is a super-3 number, since 3×1011211300³ (a number of 28 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is not an unprimeable number, because it can be changed into a prime (1011211303) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 207694 + ... + 212506.

It is an arithmetic number, because the mean of its divisors is an integer number (33428416).

Almost surely, 2^1011211300 is an apocalyptic number.

1011211300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1011211300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1203422976).

1011211300 is an abundant number, since it is smaller than the sum of its proper divisors (1395634652).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011211300 is a wasteful number, since it uses less digits than its factorization.

1011211300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5029 (or 5022 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 1011211300 is about 31799.5487389365. The cubic root of 1011211300 is about 1003.7232204254.

Adding to 1011211300 its reverse (31121101), we get a palindrome (1042332401).

It can be divided in two parts, 10112 and 11300, that added together give a palindrome (21412).

The spelling of 1011211300 in words is "one billion, eleven million, two hundred eleven thousand, three hundred".