10112120121119 has 2 divisors, whose sum is σ = 10112120121120. Its totient is φ = 10112120121118.

The previous prime is 10112120121083. The next prime is 10112120121121. The reversal of 10112120121119 is 91112102121101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10112120121119 - 2³² = 10107825153823 is a prime.

It is a super-2 number, since 2×10112120121119² (a number of 27 digits) contains 22 as substring.

Together with 10112120121121, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10112120121094 and 10112120121103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112120121619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056060060559 + 5056060060560.

It is an arithmetic number, because the mean of its divisors is an integer number (5056060060560).

Almost surely, 2^{10112120121119} is an apocalyptic number.

10112120121119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112120121119 is an equidigital number, since it uses as much as digits as its factorization.

10112120121119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 23.

The spelling of 10112120121119 in words is "ten trillion, one hundred twelve billion, one hundred twenty million, one hundred twenty-one thousand, one hundred nineteen".