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10112202013 is a prime number
BaseRepresentation
bin10010110101011101…
…11111010100011101
3222002201220002100111
421122232333110131
5131202210431023
64351231330021
7505406204344
oct113256772435
928081802314
1010112202013
11431a090051
121b62680911
13c52013bb4
146bd00cb5b
153e2b7300d
hex25abbf51d

10112202013 has 2 divisors, whose sum is σ = 10112202014. Its totient is φ = 10112202012.

The previous prime is 10112202007. The next prime is 10112202017. The reversal of 10112202013 is 31020221101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9491046084 + 621155929 = 97422^2 + 24923^2 .

It is an emirp because it is prime and its reverse (31020221101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10112202013 - 221 = 10110104861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10112201984 and 10112202002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112202017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056101006 + 5056101007.

It is an arithmetic number, because the mean of its divisors is an integer number (5056101007).

Almost surely, 210112202013 is an apocalyptic number.

It is an amenable number.

10112202013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112202013 is an equidigital number, since it uses as much as digits as its factorization.

10112202013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10112202013 its reverse (31020221101), we get a palindrome (41132423114).

The spelling of 10112202013 in words is "ten billion, one hundred twelve million, two hundred two thousand, thirteen".