101122101222113 has 2 divisors, whose sum is σ = 101122101222114. Its totient is φ = 101122101222112.

The previous prime is 101122101222073. The next prime is 101122101222133. The reversal of 101122101222113 is 311222101221101.

It is an a-pointer prime, because the next prime (101122101222133) can be obtained adding 101122101222113 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66757919984704 + 34364181237409 = 8170552^2 + 5862097^2 .

It is a cyclic number.

It is not a de Polignac number, because 101122101222113 - 2²⁰ = 101122100173537 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (101122101222133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50561050611056 + 50561050611057.

It is an arithmetic number, because the mean of its divisors is an integer number (50561050611057).

Almost surely, 2^{101122101222113} is an apocalyptic number.

It is an amenable number.

101122101222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101122101222113 is an equidigital number, since it uses as much as digits as its factorization.

101122101222113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 101122101222113 its reverse (311222101221101), we get a palindrome (412344202443214).

The spelling of 101122101222113 in words is "one hundred one trillion, one hundred twenty-two billion, one hundred one million, two hundred twenty-two thousand, one hundred thirteen".