Search a number
-
+
10112211023 is a prime number
BaseRepresentation
bin10010110101011110…
…00001100001001111
3222002201220112201012
421122233001201033
5131202211223043
64351231435435
7505406242535
oct113257014117
928081815635
1010112211023
11431a0968a2
121b62685b7b
13c52018025
146bd012155
153e2b75a18
hex25abc184f

10112211023 has 2 divisors, whose sum is σ = 10112211024. Its totient is φ = 10112211022.

The previous prime is 10112211019. The next prime is 10112211059. The reversal of 10112211023 is 32011221101.

10112211023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (32011221101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10112211023 - 22 = 10112211019 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 10112210989 and 10112211007.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10112211223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056105511 + 5056105512.

It is an arithmetic number, because the mean of its divisors is an integer number (5056105512).

Almost surely, 210112211023 is an apocalyptic number.

10112211023 is a deficient number, since it is larger than the sum of its proper divisors (1).

10112211023 is an equidigital number, since it uses as much as digits as its factorization.

10112211023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 10112211023 its reverse (32011221101), we get a palindrome (42123432124).

The spelling of 10112211023 in words is "ten billion, one hundred twelve million, two hundred eleven thousand, twenty-three".