Base | Representation |
---|---|
bin | 1001001100100110111011… |
… | …0100001110101100110111 |
3 | 1022210201101110021122102221 |
4 | 2103021232310032230313 |
5 | 2311134302310401442 |
6 | 33301253001543211 |
7 | 2062404021326203 |
oct | 223115664165467 |
9 | 38721343248387 |
10 | 10112212200247 |
11 | 32496241869a3 |
12 | 11739934a4b07 |
13 | 584767a68c51 |
14 | 26d610047b03 |
15 | 128096367467 |
hex | 9326ed0eb37 |
10112212200247 has 2 divisors, whose sum is σ = 10112212200248. Its totient is φ = 10112212200246.
The previous prime is 10112212200199. The next prime is 10112212200263. The reversal of 10112212200247 is 74200221221101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10112212200247 - 243 = 1316119178039 is a prime.
It is a super-2 number, since 2×101122122002472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10112212200047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056106100123 + 5056106100124.
It is an arithmetic number, because the mean of its divisors is an integer number (5056106100124).
Almost surely, 210112212200247 is an apocalyptic number.
10112212200247 is a deficient number, since it is larger than the sum of its proper divisors (1).
10112212200247 is an equidigital number, since it uses as much as digits as its factorization.
10112212200247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 10112212200247 its reverse (74200221221101), we get a palindrome (84312433421348).
The spelling of 10112212200247 in words is "ten trillion, one hundred twelve billion, two hundred twelve million, two hundred thousand, two hundred forty-seven".
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