Base | Representation |
---|---|
bin | 11101011011100100100… |
… | …00001001001000101101 |
3 | 10120200011122110022122021 |
4 | 32231302100021020231 |
5 | 113032001420231114 |
6 | 2052315441150141 |
7 | 133026216304525 |
oct | 16556220111055 |
9 | 3520148408567 |
10 | 1011234148909 |
11 | 35a953350286 |
12 | 143b9832b351 |
13 | 74488875a2a |
14 | 36d30468685 |
15 | 1b487b58024 |
hex | eb7240922d |
1011234148909 has 2 divisors, whose sum is σ = 1011234148910. Its totient is φ = 1011234148908.
The previous prime is 1011234148907. The next prime is 1011234148949. The reversal of 1011234148909 is 9098414321101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 695105712900 + 316128436009 = 833730^2 + 562253^2 .
It is a cyclic number.
It is not a de Polignac number, because 1011234148909 - 21 = 1011234148907 is a prime.
Together with 1011234148907, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011234148907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505617074454 + 505617074455.
It is an arithmetic number, because the mean of its divisors is an integer number (505617074455).
Almost surely, 21011234148909 is an apocalyptic number.
It is an amenable number.
1011234148909 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011234148909 is an equidigital number, since it uses as much as digits as its factorization.
1011234148909 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 43.
The spelling of 1011234148909 in words is "one trillion, eleven billion, two hundred thirty-four million, one hundred forty-eight thousand, nine hundred nine".
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