Base | Representation |
---|---|
bin | 10110111111100100001110… |
… | …101011000011010100010011 |
3 | 111021001110221121212200101211 |
4 | 112333210032223003110103 |
5 | 101223314003243313443 |
6 | 555024144332040551 |
7 | 30205025665126213 |
oct | 2677441653032423 |
9 | 437043847780354 |
10 | 101125251151123 |
11 | 2a248a83a43801 |
12 | b412902003157 |
13 | 44570bb4b1054 |
14 | 1ad86b9b5c243 |
15 | ba577700319d |
hex | 5bf90eac3513 |
101125251151123 has 2 divisors, whose sum is σ = 101125251151124. Its totient is φ = 101125251151122.
The previous prime is 101125251151121. The next prime is 101125251151139. The reversal of 101125251151123 is 321151152521101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101125251151123 - 21 = 101125251151121 is a prime.
It is a super-2 number, since 2×1011252511511232 (a number of 29 digits) contains 22 as substring.
Together with 101125251151121, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (101125251151121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50562625575561 + 50562625575562.
It is an arithmetic number, because the mean of its divisors is an integer number (50562625575562).
Almost surely, 2101125251151123 is an apocalyptic number.
101125251151123 is a deficient number, since it is larger than the sum of its proper divisors (1).
101125251151123 is an equidigital number, since it uses as much as digits as its factorization.
101125251151123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3000, while the sum is 31.
The spelling of 101125251151123 in words is "one hundred one trillion, one hundred twenty-five billion, two hundred fifty-one million, one hundred fifty-one thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.118 sec. • engine limits •