101129117 has 2 divisors, whose sum is σ = 101129118. Its totient is φ = 101129116.

The previous prime is 101129113. The next prime is 101129159. The reversal of 101129117 is 711921101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96609241 + 4519876 = 9829^2 + 2126^2 .

It is an emirp because it is prime and its reverse (711921101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101129117 - 2² = 101129113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101129092 and 101129101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101129113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50564558 + 50564559.

It is an arithmetic number, because the mean of its divisors is an integer number (50564559).

Almost surely, 2^101129117 is an apocalyptic number.

It is an amenable number.

101129117 is a deficient number, since it is larger than the sum of its proper divisors (1).

101129117 is an equidigital number, since it uses as much as digits as its factorization.

101129117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 23.

The square root of 101129117 is about 10056.2973802489. The cubic root of 101129117 is about 465.8993148225.

The spelling of 101129117 in words is "one hundred one million, one hundred twenty-nine thousand, one hundred seventeen".