10113013111 has 2 divisors, whose sum is σ = 10113013112. Its totient is φ = 10113013110.

The previous prime is 10113013109. The next prime is 10113013121. The reversal of 10113013111 is 11131031101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10113013111 - 2¹ = 10113013109 is a prime.

Together with 10113013109, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10113013091 and 10113013100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10113013121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056506555 + 5056506556.

It is an arithmetic number, because the mean of its divisors is an integer number (5056506556).

Almost surely, 2^10113013111 is an apocalyptic number.

10113013111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113013111 is an equidigital number, since it uses as much as digits as its factorization.

10113013111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 10113013111 its reverse (11131031101), we get a palindrome (21244044212).

The spelling of 10113013111 in words is "ten billion, one hundred thirteen million, thirteen thousand, one hundred eleven".