1011304011303 has 48 divisors (see below), whose sum is σ = 1484221078080. Its totient is φ = 663474240000.

The previous prime is 1011304011259. The next prime is 1011304011317. The reversal of 1011304011303 is 3031104031101.

1011304011303 is a `hidden beast` number, since 1 + 0 + 1 + 130 + 401 + 130 + 3 = 666.

It is not a de Polignac number, because 1011304011303 - 2¹³ = 1011304003111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011304011703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 102136653 + ... + 102146553.

It is an arithmetic number, because the mean of its divisors is an integer number (30921272460).

Almost surely, 2^{1011304011303} is an apocalyptic number.

1011304011303 is a deficient number, since it is larger than the sum of its proper divisors (472917066777).

1011304011303 is a wasteful number, since it uses less digits than its factorization.

1011304011303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10680 (or 10677 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1011304011303 its reverse (3031104031101), we get a palindrome (4042408042404).

The spelling of 1011304011303 in words is "one trillion, eleven billion, three hundred four million, eleven thousand, three hundred three".