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101131123329491 is a prime number
BaseRepresentation
bin10110111111101001101100…
…101011101000100111010011
3111021002001002212102020202112
4112333221230223220213103
5101223413020033020431
6555030555141135535
730205324340615603
oct2677515453504723
9437061085366675
10101131123329491
112a250517700282
12b413a806ba5ab
134457815c449c8
141ad8ab59b6c03
15ba59bc7dcc2b
hex5bfa6cae89d3

101131123329491 has 2 divisors, whose sum is σ = 101131123329492. Its totient is φ = 101131123329490.

The previous prime is 101131123329409. The next prime is 101131123329493. The reversal of 101131123329491 is 194923321131101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101131123329491 - 222 = 101131119135187 is a prime.

Together with 101131123329493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (101131123329493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565561664745 + 50565561664746.

It is an arithmetic number, because the mean of its divisors is an integer number (50565561664746).

Almost surely, 2101131123329491 is an apocalyptic number.

101131123329491 is a deficient number, since it is larger than the sum of its proper divisors (1).

101131123329491 is an equidigital number, since it uses as much as digits as its factorization.

101131123329491 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 41.

The spelling of 101131123329491 in words is "one hundred one trillion, one hundred thirty-one billion, one hundred twenty-three million, three hundred twenty-nine thousand, four hundred ninety-one".