Base | Representation |
---|---|
bin | 10110111111101001101100… |
… | …101011101000100111010011 |
3 | 111021002001002212102020202112 |
4 | 112333221230223220213103 |
5 | 101223413020033020431 |
6 | 555030555141135535 |
7 | 30205324340615603 |
oct | 2677515453504723 |
9 | 437061085366675 |
10 | 101131123329491 |
11 | 2a250517700282 |
12 | b413a806ba5ab |
13 | 4457815c449c8 |
14 | 1ad8ab59b6c03 |
15 | ba59bc7dcc2b |
hex | 5bfa6cae89d3 |
101131123329491 has 2 divisors, whose sum is σ = 101131123329492. Its totient is φ = 101131123329490.
The previous prime is 101131123329409. The next prime is 101131123329493. The reversal of 101131123329491 is 194923321131101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101131123329491 - 222 = 101131119135187 is a prime.
Together with 101131123329493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (101131123329493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565561664745 + 50565561664746.
It is an arithmetic number, because the mean of its divisors is an integer number (50565561664746).
Almost surely, 2101131123329491 is an apocalyptic number.
101131123329491 is a deficient number, since it is larger than the sum of its proper divisors (1).
101131123329491 is an equidigital number, since it uses as much as digits as its factorization.
101131123329491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 101131123329491 in words is "one hundred one trillion, one hundred thirty-one billion, one hundred twenty-three million, three hundred twenty-nine thousand, four hundred ninety-one".
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