Base | Representation |
---|---|
bin | 10010110101100101… |
… | …00000000010101101 |
3 | 222002210121211222202 |
4 | 21122302200002231 |
5 | 131202424404402 |
6 | 4351303151245 |
7 | 505420060043 |
oct | 113262400255 |
9 | 28083554882 |
10 | 10113122477 |
11 | 431a659667 |
12 | 1b62a45525 |
13 | c52276b53 |
14 | 6bd1ac393 |
15 | 3e2ca5b02 |
hex | 25aca00ad |
10113122477 has 2 divisors, whose sum is σ = 10113122478. Its totient is φ = 10113122476.
The previous prime is 10113122387. The next prime is 10113122479. The reversal of 10113122477 is 77422131101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10082971396 + 30151081 = 100414^2 + 5491^2 .
It is a cyclic number.
It is not a de Polignac number, because 10113122477 - 222 = 10108928173 is a prime.
Together with 10113122479, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10113122479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056561238 + 5056561239.
It is an arithmetic number, because the mean of its divisors is an integer number (5056561239).
Almost surely, 210113122477 is an apocalyptic number.
It is an amenable number.
10113122477 is a deficient number, since it is larger than the sum of its proper divisors (1).
10113122477 is an equidigital number, since it uses as much as digits as its factorization.
10113122477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2352, while the sum is 29.
Adding to 10113122477 its reverse (77422131101), we get a palindrome (87535253578).
The spelling of 10113122477 in words is "ten billion, one hundred thirteen million, one hundred twenty-two thousand, four hundred seventy-seven".
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