Search a number
-
+
101131322312183 is a prime number
BaseRepresentation
bin10110111111101001111000…
…100010101100010111110111
3111021002001121201211121200212
4112333221320202230113313
5101223413422002442213
6555031031010100035
730205332305135222
oct2677517042542767
9437061551747625
10101131322312183
112a250609a58989
12b413b1727a61b
134457848233c47
141ad8ad41b25b9
15ba59ceee59a8
hex5bfa788ac5f7

101131322312183 has 2 divisors, whose sum is σ = 101131322312184. Its totient is φ = 101131322312182.

The previous prime is 101131322312147. The next prime is 101131322312233. The reversal of 101131322312183 is 381213223131101.

It is a weak prime.

It is an emirp because it is prime and its reverse (381213223131101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101131322312183 - 218 = 101131322050039 is a prime.

It is a super-2 number, since 2×1011313223121832 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101131322311183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50565661156091 + 50565661156092.

It is an arithmetic number, because the mean of its divisors is an integer number (50565661156092).

Almost surely, 2101131322312183 is an apocalyptic number.

101131322312183 is a deficient number, since it is larger than the sum of its proper divisors (1).

101131322312183 is an equidigital number, since it uses as much as digits as its factorization.

101131322312183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 32.

Adding to 101131322312183 its reverse (381213223131101), we get a palindrome (482344545443284).

The spelling of 101131322312183 in words is "one hundred one trillion, one hundred thirty-one billion, three hundred twenty-two million, three hundred twelve thousand, one hundred eighty-three".