10113213120000 has 400 divisors, whose sum is σ = 33827249715072. Its totient is φ = 2684021760000.

The previous prime is 10113213119981. The next prime is 10113213120029. The reversal of 10113213120000 is 2131231101.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (400).

It is a super-2 number, since 2×10113213120000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 202535037 + ... + 202584963.

Almost surely, 2^{10113213120000} is an apocalyptic number.

10113213120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10113213120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16913624857536).

10113213120000 is an abundant number, since it is smaller than the sum of its proper divisors (23714036595072).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10113213120000 is an frugal number, since it uses more digits than its factorization.

10113213120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50179 (or 50148 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 10113213120000 its reverse (2131231101), we get a palindrome (10115344351101).

The spelling of 10113213120000 in words is "ten trillion, one hundred thirteen billion, two hundred thirteen million, one hundred twenty thousand".