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10113220130231 is a prime number
BaseRepresentation
bin1001001100101010101011…
…1001001011010110110111
31022210210222200212210110002
42103022222321023112313
52311143333323131411
633301541005221515
72062441010515451
oct223125271132667
938723880783402
1010113220130231
113249aa1126689
121174014b6189b
1358489882171a
1426d6a7c5b2d1
15128104ab333b
hex932aae4b5b7

10113220130231 has 2 divisors, whose sum is σ = 10113220130232. Its totient is φ = 10113220130230.

The previous prime is 10113220130227. The next prime is 10113220130359. The reversal of 10113220130231 is 13203102231101.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (13203102231101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10113220130231 - 22 = 10113220130227 is a prime.

It is a super-2 number, since 2×101132201302312 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10113220130201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5056610065115 + 5056610065116.

It is an arithmetic number, because the mean of its divisors is an integer number (5056610065116).

Almost surely, 210113220130231 is an apocalyptic number.

10113220130231 is a deficient number, since it is larger than the sum of its proper divisors (1).

10113220130231 is an equidigital number, since it uses as much as digits as its factorization.

10113220130231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 10113220130231 its reverse (13203102231101), we get a palindrome (23316322361332).

The spelling of 10113220130231 in words is "ten trillion, one hundred thirteen billion, two hundred twenty million, one hundred thirty thousand, two hundred thirty-one".