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101132331414047 is a prime number
BaseRepresentation
bin10110111111101010110100…
…101100000111001000011111
3111021002011020001122022012222
4112333222310230013020133
5101223423003320222142
6555031315054415555
730205366310305163
oct2677526454071037
9437064201568188
10101132331414047
112a250a8762906a
12b4141592015bb
134457979309c3b
141ad8b8c20cca3
15ba5a3d8c3bd2
hex5bfab4b0721f

101132331414047 has 2 divisors, whose sum is σ = 101132331414048. Its totient is φ = 101132331414046.

The previous prime is 101132331414029. The next prime is 101132331414097. The reversal of 101132331414047 is 740414133231101.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101132331414047 - 210 = 101132331413023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101132331413998 and 101132331414016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101132331414097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50566165707023 + 50566165707024.

It is an arithmetic number, because the mean of its divisors is an integer number (50566165707024).

Almost surely, 2101132331414047 is an apocalyptic number.

101132331414047 is a deficient number, since it is larger than the sum of its proper divisors (1).

101132331414047 is an equidigital number, since it uses as much as digits as its factorization.

101132331414047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

Adding to 101132331414047 its reverse (740414133231101), we get a palindrome (841546464645148).

The spelling of 101132331414047 in words is "one hundred one trillion, one hundred thirty-two billion, three hundred thirty-one million, four hundred fourteen thousand, forty-seven".