Base | Representation |
---|---|
bin | 101111000101111110… |
… | …1100100010001001101 |
3 | 100200001002111020200121 |
4 | 1132023331210101031 |
5 | 3124104344421143 |
6 | 114243134424541 |
7 | 10210104250021 |
oct | 1361375442115 |
9 | 320032436617 |
10 | 101132420173 |
11 | 39987684144 |
12 | 17725062151 |
13 | 96c9301b55 |
14 | 4c755dc381 |
15 | 296d8767ed |
hex | 178bf6444d |
101132420173 has 2 divisors, whose sum is σ = 101132420174. Its totient is φ = 101132420172.
The previous prime is 101132420167. The next prime is 101132420189. The reversal of 101132420173 is 371024231101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96334502884 + 4797917289 = 310378^2 + 69267^2 .
It is a cyclic number.
It is not a de Polignac number, because 101132420173 - 25 = 101132420141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101132420153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50566210086 + 50566210087.
It is an arithmetic number, because the mean of its divisors is an integer number (50566210087).
Almost surely, 2101132420173 is an apocalyptic number.
It is an amenable number.
101132420173 is a deficient number, since it is larger than the sum of its proper divisors (1).
101132420173 is an equidigital number, since it uses as much as digits as its factorization.
101132420173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 101132420173 its reverse (371024231101), we get a palindrome (472156651274).
The spelling of 101132420173 in words is "one hundred one billion, one hundred thirty-two million, four hundred twenty thousand, one hundred seventy-three".
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