10113310000 has 50 divisors (see below), whose sum is σ = 24485359052. Its totient is φ = 4045320000.

The previous prime is 10113309991. The next prime is 10113310019. The reversal of 10113310000 is 1331101.

10113310000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (50).

It is a super-3 number, since 3×10113310000³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 495666 + ... + 515665.

Almost surely, 2^10113310000 is an apocalyptic number.

10113310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

10113310000 is an abundant number, since it is smaller than the sum of its proper divisors (14372049052).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10113310000 is an equidigital number, since it uses as much as digits as its factorization.

10113310000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1011359 (or 1011338 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 10113310000 its reverse (1331101), we get a palindrome (10114641101).

The spelling of 10113310000 in words is "ten billion, one hundred thirteen million, three hundred ten thousand".