101133111230 has 16 divisors (see below), whose sum is σ = 185474310624. Its totient is φ = 39689975520.

The previous prime is 101133111229. The next prime is 101133111241. The reversal of 101133111230 is 32111331101.

It is a super-2 number, since 2×101133111230² (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101133111199 and 101133111208.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 95408066 + ... + 95409125.

It is an arithmetic number, because the mean of its divisors is an integer number (11592144414).

Almost surely, 2^101133111230 is an apocalyptic number.

101133111230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

101133111230 is a deficient number, since it is larger than the sum of its proper divisors (84341199394).

101133111230 is a wasteful number, since it uses less digits than its factorization.

101133111230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190817251.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 101133111230 its reverse (32111331101), we get a palindrome (133244442331).

It can be divided in two parts, 101 and 133111230, that added together give a palindrome (133111331).

The spelling of 101133111230 in words is "one hundred one billion, one hundred thirty-three million, one hundred eleven thousand, two hundred thirty".