101133230111 has 2 divisors, whose sum is σ = 101133230112. Its totient is φ = 101133230110.

The previous prime is 101133230087. The next prime is 101133230113. The reversal of 101133230111 is 111032331101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101133230111 is a prime.

Together with 101133230113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101133230111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101133230113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50566615055 + 50566615056.

It is an arithmetic number, because the mean of its divisors is an integer number (50566615056).

Almost surely, 2^101133230111 is an apocalyptic number.

101133230111 is a deficient number, since it is larger than the sum of its proper divisors (1).

101133230111 is an equidigital number, since it uses as much as digits as its factorization.

101133230111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 101133230111 its reverse (111032331101), we get a palindrome (212165561212).

The spelling of 101133230111 in words is "one hundred one billion, one hundred thirty-three million, two hundred thirty thousand, one hundred eleven".