Base | Representation |
---|---|
bin | 101111000110000001… |
… | …1101011011010101101 |
3 | 100200001012111122102021 |
4 | 1132030003223122231 |
5 | 3124110302203232 |
6 | 114243233030141 |
7 | 10210124002006 |
oct | 1361403533255 |
9 | 320035448367 |
10 | 101134022317 |
11 | 39988578929 |
12 | 177256b5351 |
13 | 96c9743173 |
14 | 4c758d81ad |
15 | 296da91397 |
hex | 178c0eb6ad |
101134022317 has 2 divisors, whose sum is σ = 101134022318. Its totient is φ = 101134022316.
The previous prime is 101134022243. The next prime is 101134022347. The reversal of 101134022317 is 713220431101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 56353537321 + 44780484996 = 237389^2 + 211614^2 .
It is a cyclic number.
It is not a de Polignac number, because 101134022317 - 215 = 101133989549 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101134022291 and 101134022300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101134022347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50567011158 + 50567011159.
It is an arithmetic number, because the mean of its divisors is an integer number (50567011159).
Almost surely, 2101134022317 is an apocalyptic number.
It is an amenable number.
101134022317 is a deficient number, since it is larger than the sum of its proper divisors (1).
101134022317 is an equidigital number, since it uses as much as digits as its factorization.
101134022317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 101134022317 its reverse (713220431101), we get a palindrome (814354453418).
The spelling of 101134022317 in words is "one hundred one billion, one hundred thirty-four million, twenty-two thousand, three hundred seventeen".
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