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1011341352101 is a prime number
BaseRepresentation
bin11101011011110001010…
…01000101110010100101
310120200110010011210202212
432231320221011302211
5113032211341231401
62052334231013205
7133031660440343
oct16557051056245
93520403153685
101011341352101
1135a9a8911663
1214400820a205
13744a4b3c082
1436d407b2993
151b492281dbb
hexeb78a45ca5

1011341352101 has 2 divisors, whose sum is σ = 1011341352102. Its totient is φ = 1011341352100.

The previous prime is 1011341352023. The next prime is 1011341352103. The reversal of 1011341352101 is 1012531431101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 759712708225 + 251628643876 = 871615^2 + 501626^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011341352101 - 226 = 1011274243237 is a prime.

It is a super-2 number, since 2×10113413521012 (a number of 25 digits) contains 22 as substring.

Together with 1011341352103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011341352103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505670676050 + 505670676051.

It is an arithmetic number, because the mean of its divisors is an integer number (505670676051).

Almost surely, 21011341352101 is an apocalyptic number.

It is an amenable number.

1011341352101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011341352101 is an equidigital number, since it uses as much as digits as its factorization.

1011341352101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 1011341352101 its reverse (1012531431101), we get a palindrome (2023872783202).

The spelling of 1011341352101 in words is "one trillion, eleven billion, three hundred forty-one million, three hundred fifty-two thousand, one hundred one".