Base | Representation |
---|---|
bin | 11101011011110001010… |
… | …01000101110011001111 |
3 | 10120200110010011210211102 |
4 | 32231320221011303033 |
5 | 113032211341232033 |
6 | 2052334231013315 |
7 | 133031660440433 |
oct | 16557051056317 |
9 | 3520403153742 |
10 | 1011341352143 |
11 | 35a9a89116a1 |
12 | 14400820a23b |
13 | 744a4b3c0b5 |
14 | 36d407b29c3 |
15 | 1b492281de8 |
hex | eb78a45ccf |
1011341352143 has 2 divisors, whose sum is σ = 1011341352144. Its totient is φ = 1011341352142.
The previous prime is 1011341352103. The next prime is 1011341352163. The reversal of 1011341352143 is 3412531431101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1011341352143 - 212 = 1011341348047 is a prime.
It is a super-3 number, since 3×10113413521433 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1011341352103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505670676071 + 505670676072.
It is an arithmetic number, because the mean of its divisors is an integer number (505670676072).
Almost surely, 21011341352143 is an apocalyptic number.
1011341352143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011341352143 is an equidigital number, since it uses as much as digits as its factorization.
1011341352143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 1011341352143 its reverse (3412531431101), we get a palindrome (4423872783244).
The spelling of 1011341352143 in words is "one trillion, eleven billion, three hundred forty-one million, three hundred fifty-two thousand, one hundred forty-three".
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