1011411300973 has 2 divisors, whose sum is σ = 1011411300974. Its totient is φ = 1011411300972.

The previous prime is 1011411300971. The next prime is 1011411300989. The reversal of 1011411300973 is 3790031141101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 844042763524 + 167368537449 = 918718^2 + 409107^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011411300973 - 2¹ = 1011411300971 is a prime.

Together with 1011411300971, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011411300971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505705650486 + 505705650487.

It is an arithmetic number, because the mean of its divisors is an integer number (505705650487).

Almost surely, 2^{1011411300973} is an apocalyptic number.

It is an amenable number.

1011411300973 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011411300973 is an equidigital number, since it uses as much as digits as its factorization.

1011411300973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2268, while the sum is 31.

The spelling of 1011411300973 in words is "one trillion, eleven billion, four hundred eleven million, three hundred thousand, nine hundred seventy-three".