Base | Representation |
---|---|
bin | 10010110101101110… |
… | …11101100101001101 |
3 | 222002220001221010121 |
4 | 21122313131211031 |
5 | 131203243014432 |
6 | 4351351104541 |
7 | 505434115021 |
oct | 113267354515 |
9 | 28086057117 |
10 | 10114423117 |
11 | 4320367877 |
12 | 1b63372151 |
13 | c52610b66 |
14 | 6bd42a381 |
15 | 3e2e61197 |
hex | 25addd94d |
10114423117 has 2 divisors, whose sum is σ = 10114423118. Its totient is φ = 10114423116.
The previous prime is 10114423031. The next prime is 10114423181. The reversal of 10114423117 is 71132441101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8152464681 + 1961958436 = 90291^2 + 44294^2 .
It is an emirp because it is prime and its reverse (71132441101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10114423117 - 223 = 10106034509 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10114423091 and 10114423100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10114423817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057211558 + 5057211559.
It is an arithmetic number, because the mean of its divisors is an integer number (5057211559).
Almost surely, 210114423117 is an apocalyptic number.
It is an amenable number.
10114423117 is a deficient number, since it is larger than the sum of its proper divisors (1).
10114423117 is an equidigital number, since it uses as much as digits as its factorization.
10114423117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 10114423117 its reverse (71132441101), we get a palindrome (81246864218).
The spelling of 10114423117 in words is "ten billion, one hundred fourteen million, four hundred twenty-three thousand, one hundred seventeen".
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