Base | Representation |
---|---|
bin | 10010110101110100… |
… | …01101100000001011 |
3 | 222002221102112120112 |
4 | 21122322031200023 |
5 | 131203434044231 |
6 | 4351414344535 |
7 | 505443205562 |
oct | 113272154013 |
9 | 28087375515 |
10 | 10115143691 |
11 | 432080a194 |
12 | 1b6365b14b |
13 | c52803b33 |
14 | 6bd576bd9 |
15 | 3e305492b |
hex | 25ae8d80b |
10115143691 has 2 divisors, whose sum is σ = 10115143692. Its totient is φ = 10115143690.
The previous prime is 10115143673. The next prime is 10115143693. The reversal of 10115143691 is 19634151101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10115143691 is a prime.
It is a super-2 number, since 2×101151436912 (a number of 21 digits) contains 22 as substring.
Together with 10115143693, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10115143693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057571845 + 5057571846.
It is an arithmetic number, because the mean of its divisors is an integer number (5057571846).
Almost surely, 210115143691 is an apocalyptic number.
10115143691 is a deficient number, since it is larger than the sum of its proper divisors (1).
10115143691 is an equidigital number, since it uses as much as digits as its factorization.
10115143691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 32.
Adding to 10115143691 its reverse (19634151101), we get a palindrome (29749294792).
The spelling of 10115143691 in words is "ten billion, one hundred fifteen million, one hundred forty-three thousand, six hundred ninety-one".
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