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1012000121213 is a prime number
BaseRepresentation
bin11101011100111111110…
…10000110000101111101
310120202011000202202002212
432232133322012011331
5113040034012334323
62052523442430205
7133054210046114
oct16563772060575
93522130682085
101012000121213
1136020675a644
12144170962365
137457b473593
1436da4096c7b
151b4d000cb78
hexeb9fe8617d

1012000121213 has 2 divisors, whose sum is σ = 1012000121214. Its totient is φ = 1012000121212.

The previous prime is 1012000121189. The next prime is 1012000121221. The reversal of 1012000121213 is 3121210002101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 694267233529 + 317732887684 = 833227^2 + 563678^2 .

It is an emirp because it is prime and its reverse (3121210002101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1012000121213 - 210 = 1012000120189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012000621213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506000060606 + 506000060607.

It is an arithmetic number, because the mean of its divisors is an integer number (506000060607).

Almost surely, 21012000121213 is an apocalyptic number.

It is an amenable number.

1012000121213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012000121213 is an equidigital number, since it uses as much as digits as its factorization.

1012000121213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 1012000121213 its reverse (3121210002101), we get a palindrome (4133210123314).

The spelling of 1012000121213 in words is "one trillion, twelve billion, one hundred twenty-one thousand, two hundred thirteen".