1012012110101 has 2 divisors, whose sum is σ = 1012012110102. Its totient is φ = 1012012110100.

The previous prime is 1012012110097. The next prime is 1012012110103. The reversal of 1012012110101 is 1010112102101.

1012012110101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 845057332900 + 166954777201 = 919270^2 + 408601^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012012110101 - 2² = 1012012110097 is a prime.

Together with 1012012110103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012012110103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006055050 + 506006055051.

It is an arithmetic number, because the mean of its divisors is an integer number (506006055051).

Almost surely, 2^{1012012110101} is an apocalyptic number.

It is an amenable number.

1012012110101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012012110101 is an equidigital number, since it uses as much as digits as its factorization.

1012012110101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1012012110101 its reverse (1010112102101), we get a palindrome (2022124212202).

The spelling of 1012012110101 in words is "one trillion, twelve billion, twelve million, one hundred ten thousand, one hundred one".