Base | Representation |
---|---|
bin | 11101011101000001001… |
… | …11110101010111000100 |
3 | 10120202011212022220102011 |
4 | 32232200213311113010 |
5 | 113040100100030200 |
6 | 2052524551424004 |
7 | 133054414004461 |
oct | 16564047652704 |
9 | 3522155286364 |
10 | 1012012111300 |
11 | 3602124a9a03 |
12 | 144174985004 |
13 | 74580ab0bc8 |
14 | 36da58d8668 |
15 | 1b4d10ca5ba |
hex | eba09f55c4 |
1012012111300 has 18 divisors (see below), whose sum is σ = 2196066281738. Its totient is φ = 404804844480.
The previous prime is 1012012111283. The next prime is 1012012111301. The reversal of 1012012111300 is 31112102101.
It is a happy number.
It can be written as a sum of positive squares in 3 ways, for example, as 333751154944 + 678260956356 = 577712^2 + 823566^2 .
It is not an unprimeable number, because it can be changed into a prime (1012012111301) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5060060457 + ... + 5060060656.
Almost surely, 21012012111300 is an apocalyptic number.
1012012111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1012012111300 is an abundant number, since it is smaller than the sum of its proper divisors (1184054170438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1012012111300 is a wasteful number, since it uses less digits than its factorization.
1012012111300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10120121127 (or 10120121120 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 1012012111300 its reverse (31112102101), we get a palindrome (1043124213401).
The spelling of 1012012111300 in words is "one trillion, twelve billion, twelve million, one hundred eleven thousand, three hundred".
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