101201212210013 has 2 divisors, whose sum is σ = 101201212210014. Its totient is φ = 101201212210012.

The previous prime is 101201212209971. The next prime is 101201212210037. The reversal of 101201212210013 is 310012212102101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100706302774009 + 494909436004 = 10035253^2 + 703498^2 .

It is an emirp because it is prime and its reverse (310012212102101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101201212210013 - 2²² = 101201208015709 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101201212209973 and 101201212210000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101201212210613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600606105006 + 50600606105007.

It is an arithmetic number, because the mean of its divisors is an integer number (50600606105007).

Almost surely, 2^{101201212210013} is an apocalyptic number.

It is an amenable number.

101201212210013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101201212210013 is an equidigital number, since it uses as much as digits as its factorization.

101201212210013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 101201212210013 its reverse (310012212102101), we get a palindrome (411213424312114).

The spelling of 101201212210013 in words is "one hundred one trillion, two hundred one billion, two hundred twelve million, two hundred ten thousand, thirteen".