101201212213101 has 96 divisors (see below), whose sum is σ = 196277557432320. Its totient is φ = 48525942326400.

The previous prime is 101201212213067. The next prime is 101201212213147. The reversal of 101201212213101 is 101312212102101.

It is a happy number.

101201212213101 is a `hidden beast` number, since 1 + 0 + 12 + 0 + 121 + 221 + 310 + 1 = 666.

101201212213101 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 101201212213101 - 2⁷ = 101201212212973 is a prime.

It is a super-2 number, since 2×101201212213101² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101201212218101) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 217596316 + ... + 218060906.

It is an arithmetic number, because the mean of its divisors is an integer number (2044557889920).

Almost surely, 2^{101201212213101} is an apocalyptic number.

101201212213101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

101201212213101 is a deficient number, since it is larger than the sum of its proper divisors (95076345219219).

101201212213101 is a wasteful number, since it uses less digits than its factorization.

101201212213101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 488807 (or 488804 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 101201212213101 its reverse (101312212102101), we get a palindrome (202513424315202).

The spelling of 101201212213101 in words is "one hundred one trillion, two hundred one billion, two hundred twelve million, two hundred thirteen thousand, one hundred one".