1012014434111 has 2 divisors, whose sum is σ = 1012014434112. Its totient is φ = 1012014434110.

The previous prime is 1012014434089. The next prime is 1012014434113. The reversal of 1012014434111 is 1114344102101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1012014434111 - 2²⁶ = 1011947325247 is a prime.

Together with 1012014434113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012014434113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506007217055 + 506007217056.

It is an arithmetic number, because the mean of its divisors is an integer number (506007217056).

Almost surely, 2^{1012014434111} is an apocalyptic number.

1012014434111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012014434111 is an equidigital number, since it uses as much as digits as its factorization.

1012014434111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1012014434111 its reverse (1114344102101), we get a palindrome (2126358536212).

The spelling of 1012014434111 in words is "one trillion, twelve billion, fourteen million, four hundred thirty-four thousand, one hundred eleven".